-5x^2+5=-50

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Solution for -5x^2+5=-50 equation:



-5x^2+5=-50
We move all terms to the left:
-5x^2+5-(-50)=0
We add all the numbers together, and all the variables
-5x^2+55=0
a = -5; b = 0; c = +55;
Δ = b2-4ac
Δ = 02-4·(-5)·55
Δ = 1100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1100}=\sqrt{100*11}=\sqrt{100}*\sqrt{11}=10\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{11}}{2*-5}=\frac{0-10\sqrt{11}}{-10} =-\frac{10\sqrt{11}}{-10} =-\frac{\sqrt{11}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{11}}{2*-5}=\frac{0+10\sqrt{11}}{-10} =\frac{10\sqrt{11}}{-10} =\frac{\sqrt{11}}{-1} $

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